Java Datatypes!!!!!!!!!!!

QUESTION:

Java has 8 primitive data types; char, boolean, byte, short, int, long, float, and double. For this exercise, we'll work with the primitives used to hold integer values (byte, short, int, and long):

• A byte is an 8-bit signed integer.
• A short is a 16-bit signed integer.
• An int is a 32-bit signed integer.
• A long is a 64-bit signed integer.

Given an input integer, you must determine which primitive data types are capable of properly storing that input.

To get you started, a portion of the solution is provided for you in the editor.

Reference: https://docs.oracle.com/javase/tutorial/java/nutsandbolts/datatypes.html

Input Format

The first line contains an integer, , denoting the number of test cases. 
Each test case, , is comprised of a single line with an integer, , which can be arbitrarily large or small.

Output Format

For each input variable  and appropriate primitive , you must determine if the given primitives are capable of storing it. If yes, then print:

n can be fitted in:
* dataType

If there is more than one appropriate data type, print each one on its own line and order them by size (i.e.: ).

If the number cannot be stored in one of the four aforementioned primitives, print the line:

n can't be fitted anywhere.

Sample Input

5
-150
150000
1500000000
213333333333333333333333333333333333
-100000000000000

Sample Output

-150 can be fitted in:
* short
* int
* long
150000 can be fitted in:
* int
* long
1500000000 can be fitted in:
* int
* long
213333333333333333333333333333333333 can't be fitted anywhere.
-100000000000000 can be fitted in:
* long

Explanation

 can be stored in a short, an int, or a long.

 is very large and is outside of the allowable range of values for the primitive data types discussed in this problem.

Solution...

import java.util.*;

import java.io.*;

class Solution{

    public static void main(String []argh)

    {

         Scanner sc = new Scanner(System.in);

         int t=sc.nextInt();

         for(int i=0;i<t;i++)

         {

            try

            {

                long x=sc.nextLong();

                System.out.println(x+" can be fitted in:");

                if(x>=-128 && x<=127)

                    System.out.println("* byte");

                //Complete the code

                if(x>= -Math.pow(2,15) && x<= Math.pow(2,15) - 1)

                    System.out.println("* short");

                if(x>= -Math.pow(2,31) && x<= Math.pow(2,31) - 1)

                    System.out.println("* int");

                if(x>= -Math.pow(2,63) && x<= Math.pow(2,63) - 1)

                    System.out.println("* long");

            }

            catch(Exception e)

            {

                System.out.println(sc.next()+" can't be fitted anywhere.");

            }

         }

    }

}

JAVA HACKERRANK PROBLEMS..

Java Output Formatting

Java's System.out.printf function can be used to print formatted output. The purpose of this exercise is to test your understanding of formatting output using printf.

To get you started, a portion of the solution is provided for you in the editor; you must format and print the input to complete the solution.

Input Format

Every line of input will contain a String followed by an integer. 
Each String will have a maximum of  alphabetic characters, and each integer will be in the inclusive range from to .

Output Format

In each line of output there should be two columns: 
The first column contains the String and is left justified using exactly  characters. 
The second column contains the integer, expressed in exactly  digits; if the original input has less than three digits, you must pad your output's leading digits with zeroes.

Sample Input

java 100
cpp 65
python 50

Sample Output

================================
java           100 
cpp            065 
python         050 
================================

Explanation

Each String is left-justified with trailing whitespace through the first  characters. The leading digit of the integer is the  character, and each integer that was less than  digits now has leading zeroes.

Solution....

import java.util.Scanner;

public class Solution {

    public static void main(String[] args) {

            Scanner sc=new Scanner(System.in);

            System.out.println("================================");

            for(int i=0;i<3;i++){

                String s1=sc.next();

                int x=sc.nextInt();

                //Complete this line

            }

            System.out.println("================================");

    }

}