JAVA HACKERRANK PROGRAMS....

 Java If-Else

In this challenge, we test your knowledge of using if-else conditional statements to automate decision-making processes. An if-else statement has the following logical flow:

Task 
Given an integer, , perform the following conditional actions:

• If  is odd, print Weird
• If  is even and in the inclusive range of  to , print Not Weird
• If  is even and in the inclusive range of  to , print Weird
• If  is even and greater than , print Not Weird

Complete the stub code provided in your editor to print whether or not  is weird.

Input Format

A single line containing a positive integer, .

Constraints

Output Format

Print Weird if the number is weird; otherwise, print Not Weird.

Sample Input 0

3

Sample Output 0

Weird

Sample Input 1

24

Sample Output 1

Not Weird

Explanation

Sample Case 0:  
 is odd and odd numbers are weird, so we print Weird.

Sample Case 1:  
 and  is even, so it isn't weird. Thus, we print Not Weird.

Solution..

    import java.io.*;

    import java.util.*;

    import java.text.*;

    import java.math.*;

    import java.util.regex.*;

    public class Solution {

        public static void main(String[] args) {

            Scanner sc=new Scanner(System.in);

            int n=sc.nextInt();            

            String ans="";

            if(n%2==1){

              ans = "Weird";

            }

            else if(n%2==0){

                 if(((n>=2) && (n<=5))||(n>20))

                     {

                     System.out.println("Not Weird");

                     }

                 else if((n>=6)&&(n<=20))  

                   {

                    System.out.println("Weird");

                   }

                  //Complete the code

                 }    

            System.out.println(ans);

            }

    }